Question

2) Rearrange the Pythagorean Theorem to solve first for c and then y.

Answer 1

`x=z-√(-y) , or, x^2=z^2-y^2\\y=z-√(-x), or, y^2=z^2-x^2`

Explanation:

I can't do much except put the Pythagorean theorem in terms of y or x.

All I did was isolate x or y by subtracting the, x or y variable from each side.

`-(y^2)+x^2 +y^2=z^2-(x^2)\\-(y^2)+x^2 +y^2=z^2-(y^2)`

Which tuns it into:

`x^2=z^2-y^2\\y^2=z^2-x^2`

And I isolated further by squaring each side, but squaring negative number is difficult and causes imaginary numbers so I just think it should stay as all of them to the power of two.