Find the area A of △JKL with vertices J(−4,10), K(0,3), and L(−4,−2).

Question

asked Jun 12, 2021 73.9k views

2 Answers

GrkEngineer · Answer 1 · 2021-06-18T09:55:01+0000

Answer:

24 sq. u.

Explanation:

1)For this triangle area, let's use the classic Euclidean formula:

$\Delta \: area=(b*h)/(2)$

2) Let's measure the lenght of the base, taking the y coordinate of J vertex and L Vertex

|10-(-2)|=|12|=12

3) Similarly to the height, taking the K and its distance to the base

|0-(-4)|=|4|=4

4) Plugging them in:

$\Delta \: area=(12*4)/(2)=24$