Question

Solve the following equation using the quadratic formula: 3(x+4)2 - 81 = 0

Answer 1

`-4\pm 3√(3)`

Explanation:

`3(x+4)^2-81=0 \\\\3(x^2+8x+16)-81=0 \\\\3x^2+24x+48-81=0 \\\\3x^2+24x-33=0 \\\\x=(-24\pm√(24^2+4(3)(33)))/(2(3))= \\\\(-24\pm√(972))/(6)= \\\\(-24\pm 18√(3))/(6)= \\\\-4\pm 3√(3)`

Hope this helps!