Question

. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH

Answer 1

`V_(HCl)=80mL`

Step-by-step explanation:

Hello,

In this case, for the given reactants we identify the following chemical reaction:

`KOH+HCl\rightarrow KCl+H_2O`

Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:

`n_(HCl)=n_(KOH)\\\\M_(HCl)V_(HCl)=M_(KOH)V_(KOH)`

Hence, we compute the volume of HCl as shown below:

`V_(HCl)=(M_(KOH)V_(KOH))/(M_(HCl)) =(0.40M*40mL)/(0.20M) \\\\V_(HCl)=80mL`

Best regards.