Please help me ..... (80)/(90) - √(50) * {19}^(2) / {23}^(2) ​

Question

Please help me .....


`(80)/(90) - √(50) * {19}^(2) / {23}^(2)`
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Answer 1

`\implies (80)/(90)-√(50) * 19^2 / 23^2`

Order of operations (PEDMAS)

1. Parentheses
2. Exponents
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

Following the order of operations,
Carry out the exponents (and radicals) first:

`\implies (80)/(90)-√(25 \cdot 2) * 361 / 529`

`\implies (80)/(90)-5√(2) * 361 / 529`

Now the multiplication and division (from left to right):

`\implies (8)/(9)-1805√(2) / 529`

`\implies (8)/(9)-(1805√(2))/(529)`

Convert the fractions so that their denominators are the same:

`\implies (8 * 529)/(9 * 529)-(1805√(2) * 9)/(529 *9)`

`\implies (4232)/(4761)-(16245√(2))/(4761)`

Answer as a fraction:

`\implies (4232-16245√(2))/(4761)`

Answer as a number:

`\implies -3.936546801... = -3.9\: \textsf{(nearest tenth)}`