Question

What is the equation of the line perpendicular to y=2/3x + 1 that passes through the point (12,-6) ?

Answer 1

y=-3/2x+12

Explanation:

perpendicular lines their gradient multiply to form -1 thus gradient line 1=2/3

gradient line 2= -3/2

equation= y=mx+c where m represents gradient

y-(-6)/x-12=-3/2

y+6/x-12=-3/2

y+6=-3/2(x-12)

y+6=-3/2x+18

y= -3/2x+18-6

y=-3/2x+12