What's the total resistance of a circuit that contains three 30 Ω resistors connected in series

Question

asked Jul 16, 2021 128k views

1 Answer

Ian Leslie · Answer 1 · 2021-07-22T21:54:34+0000

Answer:

The total resistance is 90 Ω

Step-by-step explanation:

When the circuit are connected in the series then we can determined the total resistance of the circuit by the formula that are mention below .

R=R1+ R2 +R3 -------Equation 1

Here
$R1=R2=R3=30 \ ohm$

Now putting the value of R1, R2 and R3 in the Equation 1

So

$R=30 + 30 + 30\\$

Therefore the total resistance of the circuit =90 Ω