Question

I need help

In y = 2^x + 1, what is the exponent?

Answer 1

• x

Explanation:

In this problem, x is the exponent as the term '2' is multiplied by itself x times. If you look a bit further, you will see there is also an invisible power on 1, but 1 raised to any exponent will be 1 itself so it isn't considered.

Answer 2

Explanation:

The natural log has a base of 'e'. That is the definition of the natural log. Therefore, using logarithm rules, 'e' to the power of the right side equals 'y':

`{e}^{ {2}^(x) + 1 } = y`