Question

A sample of gas occupies 15.0 liters at a pressure of 2.00 atmosphere and a temperature of 300. K. If the pressure is lowered to 1.0 atmosphere and the temperature is raised to 400. K, the volume of the gas sample would be?

Answer 1

THE NEW VOLUME OF THE GAS SAMPLE IS 40 L AT 1 atm AND 400 K

Step-by-step explanation:

Using general gas equation which combines Boyle's and Charles' law, the volume of the gas sample at the new pressure and temperature can be obtained.

P1V1/T1 = P2V2/T2

P1 = Initial pressure = 2 atm

V1 = Initial volume = 15 L

T1 = Initial temperature = 300 K

P2 = Final pressure = 1 atm

T2 = Final temperature = 400 K

V2 = Final volume = unknown

Substituting the values into the equation, we have;

V2 = P1V1T2 / P2 T1

V2 = 2 * 15 * 400 / 1 * 300

V2 = 12 000/ 300

V2 = 40 L

The new volume after the pressure was reduced to 1 atm and the temperature increased to 400 K is 40 L.