Question

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Answer 1

`k=0` and
`k=3`.

Explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of
`k` that makes those coordinates equal.

`k^(2)=3k\\ k^(2)-3k=0\\k(k-3)=0\\`

Using the null factor property, we have

`k=0\\k-3=0 \implies k=3`

Therefore, the given relation is not a function when
`k=0` and
`k=3`.