Question

A sample of sugar (C12H22O11) contains

1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample? Answer without doing any calculations.

0.25 mol

0.50 mol

1.00 mol

2.50 mol

Answer 1

0.25 mol

Step-by-step explanation:

Use the formula n=N/NA

n= number of mols

N = number of particles

Nᵃ = Avogadros constant = 6.02 x
`\\10^{23`

So, n=
`(1.505 X 10^(23) )/(6.02 X 10^(23))`

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)