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1 vote
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation 2x2 + 4x + 8 = 0.

Which explanation could Anderson provide?
The equation has no real number solutions because the discriminant is 0.
The equation has one real number solution because the discriminant is 0.
O The equation has no real number solutions because the discriminant is less than 0.
The equation has two real number solutions because the discriminant is greater than 0.
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2 Answers

6 votes

Answer:

It's c

Explanation:

answered
User KernelCurry
by
8.3k points
2 votes

Answer:

No real number solutions.

Explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

The discriminant is b² - 4ac

• If b² - 4ac > 0 the equation has 2 real and distinct roots

• If b² - 4ac = 0 the equation has 2 real and equal roots

• If b² - 4ac < 0 the equation has no real roots

Given

2x² + 4x + 8 = 0 ← in standard form

with a = 2, b = 4 and c = 8, then

b² - 4ac = 4² - (4 × 2 × 8) = 16 - 64 = - 48 , thus

The equation has no real number solutions because the discriminant is < 0

answered
User Zeke Nierenberg
by
8.3k points
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