asked 59.9k views
3 votes
Sec²θ=4+2tan²θ
Find θ​

asked
User Akxaya
by
7.3k points

1 Answer

5 votes

Recall the Pythagorean identity,


\sec^2\theta=1+\tan^2\theta

So we have


\sec^2\theta=4+2\tan^2\theta


1+\tan^2\theta=4+2\tan^2\theta


-3=\tan^2\theta

But squaring any real number always gives a non-negative number, so there are no real solutions to this equation.

answered
User Edhnb
by
7.8k points
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