Question

I need help , I keep coming up with the wrong answers!

Answer 1

`x=(7\pm√(17))/(4)`

Explanation:

First of all, write the equation in standard form. Then identify a, b, c and fill in the values in the formula.

`4x^2-9x=2x^2-2x-4\\\\4x^2 -9x -(2x^2-2x-4) = 0\quad\text{subtract right side}\\\\4x^2-9x-2x^2+2x+4=0\quad\text{eliminate parentheses}\\\\2x^2 -7x+4=0\quad\text{collect terms; a=2, b=-7, c=4}\\\\x=(-b\pm√(b^2-4ac))/(2a)\quad\text{quadratic formula}\\\\x=(-(-7)\pm√((-7)^2-4(2)(4)))/(2(2))\quad\text{fill in a, b, c}\\\\\boxed{x=(7\pm√(17))/(4)}\quad\text{simplify}`