Question

The partial pressure of carbon dioxide in a mixture is 0.31 atm.

If the mole fraction of the carbon dioxide is 0.46, what is the

total pressure of the mixture?

Answer 1

`P_(Co2)= X_(Co2) P_(tot)`

Where
`P_(tot)` represent the total pressure and
`X_(Co2)` the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

`P_(tot)= (P_(Co2))/(X_(Co2))`

And replacing we got:

`P_(tot)= (0.31 atm)/(0.46)= 0.674 atm`

Explanation:

For this case the partial presure of carbon dioxide is given by:

`P_(Co2)= X_(Co2) P_(tot)`

Where
`P_(tot)` represent the total pressure and
`x_(Co2)` the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

`P_(tot)= (P_(Co2))/(X_(Co2))`

And replacing we got:

`P_(tot)= (0.31 atm)/(0.46)= 0.674 atm`