Question

In ΔMNO, the measure of ∠O=90°, the measure of ∠M=39°, and MN = 5.3 feet. Find the length of NO to the nearest tenth of a foot.

Answer 1

3.3 ft

Explanation:

Side NO is opposite the angle M, so the applicable trig relation is ...

Sin = Opposite/Hypotenuse

Opposite = Hypotenuse×Sin

NO = MN×sin(39°) = (5.3 ft)sin(39°)

NO ≈ 3.3 ft