Question

NEED TO BE ANSWERED ASAP

In a right triangle, the measure of one acute angle is twice the difference of the measure of the other acute
angle and 24. Find the measure of each acute angle in the right triangle,

Answer 1

`\alpha = 46\º \\\beta =2(46\º-24\º)= 44\º \\\theta=90\º`

Explanation:

We have:

`\alpha = x\\\beta =2(x-24\º)\\\theta=90\º`

We gotta find
`\alpha \text{ and } \beta`

Once the sum of internal angles in a right triangle is 180º

`\alpha +\beta +\theta = 180\º`

`x+2(x-24\º) +90\º = 180\º\\x+2x-48\º +90\º = 180\º\\3x = 180\º+48\º-90\º\\3x = 138\º\\x=46\º`