Question

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of the height of the big locker what is the total volume of one big locker and one small locker

Answer 1

Volume of big locker = 0.36
`m^(3)`

Volume of small locker = 0.18
`m^(3)`

Total volume = 0.54
`m^(3)`

Explanation:

We are given the following:

Width of larger locker = 0.5 m

Depth of larger locker = 0.6 m

Height of larger locker = 1.2 m

It is a cuboid like structure and it is well known that Volume of a cuboid structure =
`\text{width} * \text{depth} * \text{height}`

So, volume of larger locker =

`0.5 * 0.6 * 1.2\\\Rightarrow .36m^(3)`

Width of smaller locker = 0.5 m

Depth of smaller locker = 0.6 m

Height of smaller locker =
`(1.2)/(2) = 0.6m`

Volume of a cuboid structure =
`\text{width} * \text{depth} * \text{height}`

So, volume of smaller locker =

`0.5 * 0.6 * 0.6\\\Rightarrow 0.18m^(3)`

Adding both the volumes, Total volume = 0.54
`m^(3)`

Answer 2

`0.54\,\,m^3`

Explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m ×
`(1.2)/(2)=0.6\,\,m` (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

=
`0.5* 0.6* 1.2+0.5* 0.6* 0.6`

`=0.5* 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3`