Question

A hair spray can has a volume of 565 mL. If the can is at 42 C and 5 atm, what volume would the hair spray occupy at STP?

Answer 1

`V_2 = 2.447` atm

Step-by-step explanation:

As we know that

`PV = nRT\\`

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin

R is the gas constant
`R = 0.08206`

V is the volume in liters

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`

Substituting the given values in above equation, we get -

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)\\(5*0.565)/(315.15) = (1*V_2)/(273)`

On rearranging, we get

`(5*0.565*273)/(315.15) = V_2\\V_2 = 2.447`

`V_2 = 2.447` atm