Question

On a map of a campground, the swimming pool is located at (2,-3), the camp store at (2,8) and the tent at (-7,8). If each unit represents 5 feet, how many feet will it be to walk from the tent to the store and then to the pool? *

Answer 1

100 ft

Explanation:

I attached an image of the campground map graphically

• I figured out the units from the pool to the store and the store to the tent by counting the units between each set of points. The distance formula could also be used, but either way you will get the same answer.
• The distance formula is
  `d=\sqrt{(x_(2)-x_(1) )^(2)+ (y_(2)-y_(1) )^(2)}`

For the distance from the store to the pool:

• Our (x₁ y₁) = (2, -3) and (x₂, y₂) = (2,8)
• Plugging these values into the formula we get
  `d=\sqrt{(2-2)^(2)+(8-(-3))^(2) } =\sqrt{0-(11)^(2) } =√(121) = 11`

For the distance from the tent to the store:

• Our (x₁ y₁) = (-7, 8) and (x₂, y₂) = (2,8)
• Plugging these values into the formula we get
  `d=\sqrt{(2-(-7))^(2)+(8-8)^(2) } =\sqrt{(9)^(2)+0 } =√(81) = 9`

Now we just need to add these two distances to find the total distance it take to walk from the tent to the store and then to the pool: 9 + 11 = 20 units

• Now since 1 unit represents 5 feet, we will need to multiply our answer by 5: 20(5) = 100 ft