Answer:
The Z score for this test is 1.3416
Explanation:
According to the data given:
Null Hypothesis is: H0: p = 0.5 
 Alternative Hypothesis is: Ha: p > 0.5 
 
Here the firm found 265 out of 500 heard pf the phone 
 
p-cap = 265/500 = 0.53 
 n (sample size) = 500 
 
Therefore, z = (p-cap – p)/√{p*(1-p)/n} 
 = (0.53 – 0.5)/√(0.5*0.5/500) 
 = 0.03/√(0.0005) 
 = 0.03/0.02236 
 = 1.3416
The Z score for this test is 1.3416