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Mark, Jhon and Stephanie, three archers, are aiming at a target. Each of them has only one shot. Mark has 1/5 chance of hitting the bullseye, Jhon has 1/4 chance and Stephanie has 1/3 chance.

a. what are the chances of the bullseye being hit

b. what are the chances that if only one of them hit the bullseye, Mark was the one who hit it.

1 Answer

3 votes

For A:

You add the probabilities to get the answer to A: = .75, or 3/4

Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.

For B:

2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)

1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2

Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10

answered
User Kurubaran
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