Question

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?

A. 74 coins

B. 75 coins

C. 76 coins

D. 77 coins

Answer 1

if x = the number of nickles and x-34 = the number of dimes then .05x + .10(x-34) = 4.85 or .15x = 8.25 x = 55

So, nickles = x = 55

dimes = (x-34) = 21

55+ 21 = 76 So, that means your answer is C. 76 coins

Explanation:

Answer 2

the correct answer is C

Explanation:

Set the 34 more nickels aside.

--> pairs of 1 nickel & 1 dime each worth 15 cents & a total of $3.15 ($4.85 - $1.70)

315/15 = 21 pairs

--> 21 dimes and 55 nickels