asked 144k views
5 votes
If 600.0 ml of air is heated from 293 k to 333 k what volume will it occupy

asked
User Ynjxsjmh
by
7.7k points

1 Answer

4 votes

Answer:

Step-by-step explanation:

V1= 600.0 mL

T1= 293 K

V2 unknown

T2= 333K

Charles law V1*T2=V2*T1

where V1 and T1 are the initial volume and temperature. V2 and T2 are the final temperature and volume.

V2=(V1*T2)/T1 = ( 600.0*333)/293= 682 mL (with significant figures)(681.911 mL before signifcant figures.)

answered
User Love Dager
by
8.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.