Question

How many moles of sodium chloride are required to prepare 500.0 mL of a 0.100 M solution?

Answer 1

0.0500 mol

Step-by-step explanation:

0.100 M solution means that 0.100 mol of NaCl are in 1L=1000 mL solution.

(0.100 mol/1000 mL) * 500 mL = 0.0500 mol

Answer 2

Molarity=Moles/Liter

0.1M solution=x moles NaCl/0.5L (since 1000mL is one liter)

Multiply both sides by 0.5 to isolate the variable x

x=0.05 moles of NaCl is needed to maintain that molarity.