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–4x – 7 = y x2 – 2x – 6 = y Which statement is true? There are no real number solutions. There is one unique real number solution at (–1, –3). There is one unique real number solution at (1, –3). There are two real number solutions at (–1, –3) and (1, –7).

asked
User Chlebta
by
8.8k points

2 Answers

1 vote

Answer:

The answer is B

Explanation:

answered
User Jbodily
by
8.3k points
3 votes

Answer:

There is one unique real number solution at (–1, –3)

Explanation:

Given the two linear equation

–4x – 7 = y ...1

x² – 2x – 6 = y ...2

Equating the left hand side of both equations since they are equal to the same variable y will give;


-4x-7=x^(2) -2x-6\\collecting\ the\ like\ terms\\x^(2) -2x+4x-6+7 = 0\\x^(2) +2x+1 = 0\\x^(2) +x+x+1 = 0\\x(x+1)+1(x+1)=0\\(x+1)^(2)=0\\ taking\ square\ root\ of\ both\ sides\\x+1 = 0\\x = -1\\

Substituting x=1 into equation 1 we have;


y=-4(-1)-7\\y=4-7\\y = -3

This means there is only one unique real number solution at (-1, -3)

answered
User Darren Greaves
by
7.6k points

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