Question

Find the radius of the circle given by this equation:

Answer 1

8

Explanation:

We know that

Equation

`{x}^(2) + {y}^(2) + 2gx + 2fy + c = 0`

Represents the equation of Circle

where

`radius = \sqrt{ {g}^(2) + {f}^(2) - c }`

On comparing the given equation with general Equation of Circle

we get

`g = - 5`

`f = 3`

`c = - 30`

On substituting these values We get

`radius = \sqrt{ { (- 5)}^(2) + {3}^(2) - ( - 30) }`

`radius = √(25 + 9 + 30 ) = √(64 ) = 8`

`radius = 8`