Question

I’m really rusty with trigonometric functions

Answer 1

`\displaystyle (3)/(14) = tan\:\theta \\ (14√(205))/(205) = cos\:\theta \\ (3√(205))/(205) = sin\:\theta`

Step-by-step explanation:

`\displaystyle (OPPOCITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOCITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOCITE) = csc\:θ \\ (ADJACENT)/(OPPOCITE) = cot\:θ`

Based on the above information, you should know how to deal with trigonometric ratios when it comes to right triangles. General triangles however, are taken to another level. They deal with the Law of Sines and Law of Cosines, but you are not there yet, so you do not need to worry.

*By the way, do not forget to use the Pythagorean Theorem to define edge c:

`\displaystyle a^2 + b^2 = c^2 \\ \\ 14^2 + 3^2 = c^2 \hookrightarrow 196 + 9 = c^2; √(205) = √(c^2) \\ \\ \boxed{√(205) = c}`

I am joyous to assist you at any time.