Question

For the function f(t) =Pe^rt , if P= 7 and r= 0.07 then what is the value of f(7) to the nearest tenth?

Answer 1

11.4

Explanation:

JUST DID ON APEX

Answer 2

A. 11.4

Explanation:

`f(t) = P e^(rt)`

Data:

P = 7

r = 0.07

Calculation:

`\begin{array}{rcl}f(t) & = &Pe^(rt)\\f(7)& = & 7 e^((0.07 * 7))\\ & = & 7 e^(0.49)\\& \approx & 7 * 1.632\\ & \approx & \mathbf{11.4}\\\end{array}`