Question

How many joules of heat are lost by 1000g of granite as it cools from 41.2 Celsius to -12.9 Celsius?

Answer 1

Answer: The amount of heat released is 42739 Joules

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat released =?

c = heat capacity of granite =
`0.790J/g^0C`

Initial temperature =
`T_i` =
`41.2^0C`

Final temperature of the calorimeter =
`T_f` =
`-12.9^0C`

Change in temperature ,
`\Delta T=T_f-T_i=(-12.9-41.2)^0C=-54.1^0C`

Putting in the values, we get:

`Q=1000g* 0.790J/g^0C* -54.1^0C=-42739J`

As heat comes out to be negative, that means the heat has been released and the amount of heat released is 42739 Joules