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A state park has a normally distributed daytime temperatures in the month of June. The mean temperature is 75 Fahrenheit and then standard deviation of 7. What is the probability the temperature is above 82F?

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User Typewar
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1 Answer

2 votes

Answer:

0.16

Explanation:

This probability is the area under the standard normal curve to the right of 82. Note that 82 is ONE standard deviation above the mean: 75 + 7 = 82.

According to the Empirical Rule, 68% of data lies within one standard deviation of the mean. In other words, 34% lies between the mean and one standard deviation above the mean. The remaining area under the standard normal curve is thus (100% - 68%), or 32%. Half of that is 16%.

The probability that the temperature is above 82, or above 1 standard deviation above the mean, is 16%, which we can also express as 0.16.

Alternatively, use a calculator with built-in statistical functions. In this case the desired result is found by executing the following command:

normcdf(82, 10000, 75, 7). The desired result is 0.1587, or approximately 0.16.

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User Scutnex
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