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Sin²a+sin²a.tan²a=tan²a​

Sin²a+sin²a.tan²a=tan²a​
asked 130k views
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Sin²a+sin²a.tan²a=tan²a​

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User PalFS
by
7.7k points

1 Answer

1 vote

Answer:

# sin²A (1+tan²A)

# sin²A(sec²A)

# sin²A(1/cos²A)

# sin²A/cos²A=tan²A

answered
User David Wengier
by
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