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1 vote
The following balls are placed in an urn: 4 red, 2 yellow, 4 blue, and 2 green. One ball is randomly drawn from the urn. What is the probability that the ball

Is either yellow or green?

1 Answer

3 votes

Answer:

1/3 as;

16.66665/100 + 16.66665/100 = 33.33/100

Convert to 12 = 4+4+2 +2 = 4/12

Explanation:

or 1/3

answered
User OblongMedulla
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