Question

A circle has a radius of square root 131 units and is centered at (0,-4.3).

Whats the equation of this circle?

Answer 1

x^2 + (y + 4.3)^2 = 131

Explanation:

The basic equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2. Here the center is (0, -4.3) and the radius is √131. Substituting as indicated, we get:

(x - 0)^2 + (y + 4.3)^2 = 131, or

x^2 + (y + 4.3)^2 = 131