Question

The equations 4 x minus 5 y = 5, 3 x + 10 y = 20, 4 x minus 5 y = negative 5, and 3 x + 10 y = negative 20 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (0, 1) and (2.5, 3). Orange line goes through (0, negative 1) and (2.5, 1). Blue line goes through (0, 2) and (3.5, 1). Pink line goes through (0, negative 2) and (3.5, negative 3). Which system of equations has a solution of approximately (–2.7, –1.2)? 4 x minus 5 y = negative 5 and 3 x + 10 y = negative 20 4 x minus 5 y = 5 and 3 x + 10 y = 20 4 x minus 5 y = 5 and 3 x + 10 y = negative 20 4 x minus 5 y = negative 5 and 3 x + 10 y = 20

Answer 1

4 x - 5 y = - 5 and 3 x + 10 y = - 20

Explanation:

4 x - 5 y = -5 (1)

3 x + 10 y = -20 (2)

Multiply (1) by 2 and add to (×)

8x - 10y = -10

3x + 10y = -20

11x = -30

x = -30/11 = -2.727272

x = -2.7

4(-30/11) - 5y = -5

5y = -65/11

y = -13/11 = -1.18181818

y = -1.2

hope this helps..

Answer 2

First one:

4 x minus 5 y = negative 5 and 3 x + 10 y = negative 20

Explanation:

4 x - 5 y = -5 (1)

3 x + 10 y = -20 (2)

Multiply (1) by 2 and add to (×)

8x - 10y = -10

3x + 10y = -20

11x = -30

x = -30/11 = -2.727272

x = -2.7

4(-30/11) - 5y = -5

5y = -65/11

y = -13/11 = -1.18181818

y = -1.2