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Identify the graph of the equation... Then find q to the nearest degree. 16x^2+2xy+y^2-16=0
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Identify the graph of the equation... Then find q to the nearest degree. 16x^2+2xy+y^2-16=0
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Apr 11, 2021
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Identify the graph of the equation... Then find q to the nearest degree.
16x^2+2xy+y^2-16=0
Mathematics
college
KNOWARTH
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KNOWARTH
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We need a picture of the graph first
Mdargacz
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Apr 12, 2021
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Mdargacz
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Answer:
ellipse ; 4 degrees
Explanation:
edge’s possible answer 2020
Todd Gardner
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Apr 16, 2021
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Todd Gardner
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