Question

The data below show the weights, in pounds, of a group of professional football players.

325, 310, 289, 288, 285, 285, 285, 280, 280, 273
The mean of the data set is 290 pounds. What is the mean absolute deviation of the data
Bel, to the nearest whole number?

Answer 1

Answer:11

Step-by-step explanation: subtract the mean weight from each weight then calculate the absolute value.

Answer 2

The Mean Absolute Deviation is 11

Explanation:

Given:

325, 310, 289, 288, 285, 285, 285, 280, 280 and 273

Mean = 290

Required:

Calculate the Mean Absolute Deviation

Provided that we have the value of the mean to be 290 from the question; the following steps will calculate the Mean Absolute Deviation

Step 1: Subtract the mean weight from each weight

325 - 290 = 35

310 - 290 = 20

289 - 290 = -1

288 - 290 = -2

285 - 290 = -5

285 - 290 = -5

285 - 290 = -5

280 - 290 = -10

280 - 290 = -10

273 - 290 = -17

Step 2: Calculate the absolute value of the each results above

|35| = 35

|20| = 20

|-1| = 1

|-2| = 2

|-5| = 5

|-5| = 5

|-5| = 5

|-10| = 10

|-10| = 10

|-17| = 17

Step 3: Calculate the mean of the data above

Mean Absolute Value =
`(35 + 20 + 1 + 2 + 5 + 5 + 5 + 10 + 10 + 17)/(10)`

Mean Absolute Value =
`(110)/(10)`

Mean Absolute Value = 11

Hence, the Mean Absolute Deviation is 11