Question

A bag contains 3 red jelly beans, 3 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that both jelly beans will be blue?

Answer 1

3/45

Explanation:

10 jelly beans in the bag

3 red jelly beans

First pick: P of red jelly bean = 3/10

Second pick P of red jelly bean = 2/9

3/10*2/9 simplified = 3/45