Question

Pythagorean theorem
a^2 + b^2 = c^2
X= ?

Answer 1

`\text{Find the one bottom side of the triangle first}\\\\\text{We know that the total length is 21, but part of it is 11, so subtract}\\\\21-11=10\\\\\text{Divide 10 by 2 because there are two sides for two triangles}\\\\10/2=5\\\\\text{Now, since we know two of the sides, we would plug in the values}\\\text{into the Pythagorean theorem and solve:}\\\\5^2+b^2=13^2\\\\25+b^2=169\\\\\text{Subtract 25 from both sides}\\\\b^2=144\\\\`

`\text{Square root both sides}\\\\√(b^2)=√(144)\\\\b=12\\\\\text{This means that x = 12}\\\\\boxed{x=12}`