Question

(e^(2x)(2x+5))/2 - e^(2x)/2+c how to simplify to 1/2e^(2x)[2x+4]+C

Answer 1

factor out (1/2)e^(2x)

Explanation:

Clearly, you factor out (1/2)e^(2x).

`(e^(2x)(2x+5))/(2)-(e^(2x))/(2)+C=(e^(2x))/(2)\cdot((2x+5)-1)+C\\\\=\boxed{(1)/(2)e^(2x)(2x+4)+C}`