Answer:
total there are 3 values of x as +5/3, -5/3 and 0
Explanation:
the given equation is
x(6x-10) (6x+10)=0
this equation can be solved as following
=0 using the formula (a+b)*(a-b)= (a^2-b^2)
here a=6x and b=10
from here we can write either x=0 or 36x^2= 100
or x^2= 100/36 and x=0
or x= ±10/6 and x=0
therefore, total there are 3 values of x as +5/3, -5/3 and 0