Question

Find the zeros of the function f(x)=8x^2 +32

Answer 1

Answer: no solution

Explanation:

`8x^(2) +32=0`

Factor out 8

`8(x^(2) +4)=0`

no solution

Why?

Think about the graph,
`x^(2)` shifted up 4 has no zeros, even with a vertical stretch of 8.