Question

If 15 g of CzHo reacts with 60.0 g of Oz, how many moles of water (H2O)

will be produced? (Hint: use what you know about limiting reactant) *
2 C2H6 + 7 O2 + 4 CO2 + 6 H2O
O 1.5 mol H20
O
1.6 mol H20
O
1.0 mol H20
O
1.1 mol H20

Answer 1

1.5 mol H2O

Step-by-step explanation:

Limiting reactant was C2H6 - 0.5 moles

Fomula became .5C2H6 + 1.75O2 = 1CO2 + 1.5H2O