The zeroes of a cubic polynomial x3 -- 27 x are ---- , ---- and -------... ( help plzz)

Question

asked Oct 3, 2021 217k views

1 Answer

Hearty · Answer 1 · 2021-10-09T02:07:03+0000

Answer:

The zeroes of a cubic polynomial
$x^(3)-27\cdot x$ are
,
-√(27) and
+√(27) .

Explanation:

The zeroes of the third-order polynomial are obtained by factorization:

$x^(3)-27\cdot x$

$x\cdot (x^(2)-27)$

$x\cdot (x+√(27))\cdot (x-√(27))$

The zeroes of a cubic polynomial
$x^(3)-27\cdot x$ are
,
-√(27) and
+√(27) .