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1 vote
Thirty­two cyclists make a seven day trip. Each cyclist requires 8.33 kg of food for the entire trip. If each cyclist wants to eat an equal amount of food each day, how many kg of food will the group be carrying at the end of day 5? 13 Hands­on experience. See pg. 2.D.4 for prep work and procedure. 14 Hands­on experience. See pg. 2.D.17 for prep work and procedure.

asked
User Yohjp
by
8.0k points

1 Answer

2 votes

Answer:

76.16 kg.

Explanation:

Although the consumption remains equivalent each day, the supply each day that is
\mathbf{(8.33)/(7)\;kg }


\bf{So,per\;person\;has\;\mathbf{1.19\;kg/day}}


\mathbf{The\;numbers\;of\;days\;left:(7-5)=2}


\bf{The\;amount\;of\;food\;left\;for\;per\;head: 1.19\;kg/day*\;2\;days=2.38\;kg}


\bf{\therefore\;\;the\;total\;amount\;of\;food\;by\;each\person:2.38\;kg*32=76.16\;kg}

So, the following answer is correct according to the explanation.

answered
User Paprika
by
8.6k points
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