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What is the vertex of y=x^2-8x+15

What is the vertex of y=x^2-8x+15
asked 34.3k views
5 votes
What is the vertex of y=x^2-8x+15

asked
User Tal Rofe
by
8.1k points

2 Answers

4 votes

Answer:

y=x^2-8x+15

Vertex P is the point where y' = 0

=> y' = 2x-8 = 0

=> x =4

=> y =4^2-4*8+15 = -1

=>P(4,-1)

answered
User Smartmarkey
by
8.4k points
6 votes

Answer:

vertex is (8, -4)

Explanation:

answered
User Fernando Gallego
by
7.4k points
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