asked 42.9k views
3 votes
¿cuales números naturales de dos cifras cumplen la condición de que su triple disminuido en 5, sea menor que su doble aumentado en 8?

asked
User Mikrasya
by
7.3k points

1 Answer

4 votes

Answer: 10, 11 and 12.

Explanation:

This translates to:

Find the natural numbers of two digits that fulfill the condition that when triple and decreased in 5, is less than the double increased in 8?

suppose that A is our number of two digits, this means that:

3*A - 5 < 2*A + 8

It makes sense to start with the smaller number of two digits, 10.

3*10 - 5 < 2*10 + 8

25 < 28

this is true.

Now let's check the next one, 11.

11*3 - 5 < 2*11 + 8

28 < 30

This is true again, now let's try with the next one, 12.

3*12 - 5 < 2*12 + 8

31 < 32

This is true again, now let's find the last one.

3*13 - 5 < 2*13 + 8

34 < 34

this is not true, so the numbers that fulfill the condition are 10, 11, and 12.

A faster way to prove it is, suppose that both sides of our inequality are equal, then find the value of A.

3*A - 5 = 2*A + 8

3*A - 2*A = 8 + 5 = 13

A = 13

This means that any number of two digits less than 13 fulfills the condition, those numbers are 10, 11, and 12.

answered
User JayK
by
8.2k points
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