Question

A circle has a radius of square root of 13 units and is centered at (-9.3,4.1) what is the equation of this circle

Answer 1

(x +9.3)^2 +(y -4.1)^2 = 13

Explanation:

The standard form equation of a circle centered at (h, k) with radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Putting your numbers into this form gives ...

(x -(-9.3))^2 +(y -4.1)^2 = (√13)^2

(x +9.3)^2 +(y -4.1)^2 = 13