Question

Iron melts at 1535°C and its enthalpy of fusion is 13.8 kJ/mol. Calculate the entropy of fusion per mole of iron.

Answer 1

`\Delta _mS=7.63(J)/(mol*K)`

Step-by-step explanation:

Hello,

In this case the entropy of fusion is associated with the enthalpy and the temperature when a solid goes liquid and takes the form:

`\Delta _mS=(\Delta _mH)/(T)`

Whereas the temperature must be in absolute Kelvins:

`\Delta _mS=(13.8kJ/mol)/((1535+273.15)K)*(1000J)/(1kJ) \\\\\Delta _mS=7.63(J)/(mol*K)`

Best regards.