Question

How do I write the Keq expression for the following reaction: 2NaHCO3(s) + heat Na2SO3(s) + CO2(g) + H2O(g)

Answer 1

`K_(eq) = [\text{CO}_(2)]\text{[H$_\mathbf{2}$O]}`

Step-by-step explanation:

`\rm 2NaHCO_(3)(s) \, \rightleftharpoons \,Na_(2)CO_(3)(s) + CO_(2)(g) + H_(2)O(g)`

The general formula for an equilibrium constant expression is

`K_(eq) = \frac{[\text{Products}]}{[\text{Reactants}]}`

Solids are not included in the equilibrium constant expression.

Thus, for this reaction,

`K_(eq) = [\textbf{CO}_{\mathbf{2}}]\textbf{[H$_\mathbf{2}$O]}`